528. Random-Pick-with-Weight
difficulty: Medium
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Given an array w
of positive integers, where w[i]
describes the weight of index i
(0-indexed), write a function pickIndex
which randomly picks an index in proportion to its weight.
For example, given an input list of values w = [2, 8], when we pick up a number out of it, the chance is that 8 times out of 10 we should pick the number 1 as the answer since it's the second element of the array (w[1] = 8).
Example 1:
Input
["Solution","pickIndex"]
[[[1]],[]]
Output
[null,0]
Explanation
Solution solution = new Solution([1]);
solution.pickIndex(); // return 0. Since there is only one single element on the array the only option is to return the first element.
Example 2:
Input
["Solution","pickIndex","pickIndex","pickIndex","pickIndex","pickIndex"]
[[[1,3]],[],[],[],[],[]]
Output
[null,1,1,1,1,0]
Explanation
Solution solution = new Solution([1, 3]);
solution.pickIndex(); // return 1. It's returning the second element (index = 1) that has probability of 3/4.
solution.pickIndex(); // return 1
solution.pickIndex(); // return 1
solution.pickIndex(); // return 1
solution.pickIndex(); // return 0. It's returning the first element (index = 0) that has probability of 1/4.
Since this is a randomization problem, multiple answers are allowed so the following outputs can be considered correct :
[null,1,1,1,1,0]
[null,1,1,1,1,1]
[null,1,1,1,0,0]
[null,1,1,1,0,1]
[null,1,0,1,0,0]
......
and so on.
Constraints:
1 <= w.length <= 10000
1 <= w[i] <= 10^5
pickIndex
will be called at most10000
times.
Method One
分析一下如何按权重随机。 假设我们有 index 0 1 2 3 4 value 1 2 3 4 5 那么我们建一个长度为15的线段,那么就知道如果能均匀的落在这个线段上, 那么我们就按权重落在 index 上了。 比如 index 0 1 2 3 4 range 0-1 1-3 3-6 6-10 10-15 注意区间的开闭需要具体问面试官,其实无所谓。 如果我们产生一个 0到1之间的随机数,乘以总长度,那就是随机的按权重选了。 即 target = Math.random() * totalSum. 如果 target = 4.5, 用我最爱的普通二分查找直到停止的模板,我们知道 left = 2, right = 1. 这里我们显然应该返回 left.
class Solution {
private int[] prefixSum;
private int totalSum;
public Solution(int[] w) {
this.prefixSum = new int[w.length];
int curSum = 0;
for(int i = 0; i < w.length; i++) {
curSum += w[i];
prefixSum[i] = curSum;
}
this.totalSum = curSum;
}
public int pickIndex() {
double target = this.totalSum * Math.random();
int left = 0;
int right = prefixSum.length - 1;
while( left <= right ) {
int pivot = left + (right - left ) / 2;
int curVal = prefixSum[pivot];
if(curVal < target ) {
left = pivot + 1;
}else {
right = pivot - 1;
}
}
return left;
}
}
/**
* Your Solution object will be instantiated and called as such:
* Solution obj = new Solution(w);
* int param_1 = obj.pickIndex();
*/
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